4x=-x^2-x-2

Solution for 4x=-x^2-x-2 equation:

4x=-x^2-x-2

We move all terms to the left:

4x-(-x^2-x-2)=0

We get rid of parentheses

x^2+x+4x+2=0

We add all the numbers together, and all the variables

x^2+5x+2=0

a = 1; b = 5; c = +2;
Δ = b2-4ac
Δ = 52-4·1·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{17}}{2*1}=\frac{-5-\sqrt{17}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{17}}{2*1}=\frac{-5+\sqrt{17}}{2}
$